jojo promin... ide o to ze ziadnu chybu mi to nehlasi absolutne ziadnu chybu, inak by som ju sem dal...
a co sa kodu tyka vyzera takto:
Kód:
<table border="1px">
<tr id="" class="child" >
<td>
<table width="100%" border="1" cellpadding="4" cellspacing="0" id="tbl">
<tr style="background-color: #c0c0c0;">
<td>Produce Date 1</td>
<td>Insepction Date 1</td>
<td>Model 1</td>
<td>SN 1</td>
<td>Name 1</td>
<td>Waiting 1</td>
<td>OK 2</td>
</tr>
<?php
include ('../db.php');
$con="SELECT * FROM db_sn JOIN projekt ON db_sn.IDx=projekt.ID";// AND id='$id'
$vypis2=mysql_query($con) or die($con."<br/>".mysql_error());
$user_cats = array();
while ($idx = mysql_fetch_row($vypis2))
{
$user_cats[] = $idx[0];
}
$con1 = "SELECT IDx, waiting FROM db_sn";
$res = mysql_query($con1) or die($con1."<br/>".mysql_error());
$checkboxes = '';
while (list($idx, $waiting) = mysql_fetch_row($res))
{
if (in_array($idx, $user_cats))
{
$checked = 'checked="checked"';
}
else
{
$checked = '';
}
$checkboxes = "<input type='checkbox' name='db_sn[]' value='".$idx."'".$checked." /> ".$waiting."<br />";
}
//***************************************************
while ($data = mysql_fetch_array($vypis2)){//(list( , $datum, $sn) = mysql_fetch_row($vypis2))
?>
<tr>
<td align="center"><?php echo($data['produce_datum']) ?></td>
<td align="center"><?php echo($data['datum']) ?></td>
<td align="center"><?php echo($data['model']) ?></td>
<td align="center"><?php echo($data['sn']) ?></td>
<td align="center"><?php echo($data['meno']) ?></td>
<td align="center"><?php echo ($checkboxes) ?></td>
<td align="center"><input id="win_ok" type="checkbox" name="win_ok" value="win_ok" /></td>
</tr>
}
mysql_close();
?>
</table>
</td>
</tr>
</table>
nefunguje to och snazim sa tomuto sllovnemu spojeniu vyhybat a odnaucit sa od neho ...
myslel som tym ze to ni nezobrazil co by malo vyberat s DB ostatne zobrazuje
som to pozrel aj cez firebug co je vo firefoxe ani tam nic neukaze