Kód:
$host = "localhost";
$username = "root";
$password = "";
$table_name = "ahoj";
mysql_connect ($host, $username, $password);
mysql_select_db ($table_name);
$query = mysql_query("SELECT * FROM 10");
# while ($zaznam = MySQL_Fetch_Array($query)) #
echo "<table>
<tr>
<td>$zaznam[ipadresa]</td>
<td>$zaznam[MACadresa]</td>
<td>$zaznam[ipradio]</td>
<td>$zaznam[heslo_radio]</td>
<td>$zaznam[adresa]</td>
<td>$zaznam[telefon]</td>
<td>$zaznam[meno]</td>
<td>$zaznam[mail]</td>
<td>$zaznam[APmeno]</td>
</tr>
</table>";
mysql_close();
Nasledne mi vypise toto:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in ..... na riadku kde zacina cyklus while...... oznaceny je #
krizikom #. Uz nadtym sedim dva dni a neviem si rady, tak pls help......